codeforces题目，用python写

本题输入三个点坐标，考察叉积，若大于0则right，小于0则left，等于0则towards

代码：

a = raw_input().split()b = raw_input().split()c = raw_input().split()xa = int(a[0])ya = int(a[1])xb = int(b[0])yb = int(b[1])xc = int(c[0])yc = int(c[1])x1 = xb - xax2 = xb - xcy1 = yb - yay2 = yb - ycres = x1 * y2 - x2 * y1if res > 0:    print "RIGHT"elif res < 0:    print "LEFT"else:    print "TOWARDS"